We may then say that, 4 is XYZ + time ergo time is inherent to XY and Z from the get go.
But what is 2, in the initial set given above?
o______X_____a i.e. X line/trajectory-of-relationship has two terminal points ( beginning and ending )
o______Y______b i.e Y line/trajectory has two terminal points
o______Z_______c i.e.Z line/ trajectory has two terminal points
Here above with three lines/trajectories we have 6, terminal points, however, three of them occupy the same point/position in space. The three o's.
Dimensions infer XYZ coordinates in space, or of space, and are best known or exemplified by three right angles extending from a single vertex/corner. This is one corner of a cube/hexa{6}hedron, and that corner/vertex above is the three o's.
or, it can also be considered as one corner of tetra{4}hedron with three right angles and one corner/vertex shared as the three o's.
In just considering the simplest scenario of observed time, as powering generalization of dual set of terminal end points ( beginning and ending ) with only the tetra{4}hedron do we arrive at the minimal, 3D volumetric polyhedron Universe with its 4 terminal points.
2 ( dual terminal points generalization/cosmic )
^2 ---and here we recall that Einstein used c^2 and shell growth of VE uses 2nd powering { if I recall correcltlyy }
4 is 4 terminal points of 3D, volumetric tetrahedron, with three right angles and one equalateral ( or other ) triangle ( hedra/face/surface ).
If any can follow the above, then please expand your mind some more with the following,
6 lines/trajectories/chords define a tetrahedron, however, we may consider that there are only 2 vectors involved. See this link to geometric synergy first. http://www.rwgrayprojects.com/synergeti ... f0801.html
If you visited the link then you can understand one vector as having 3 parts ergo a frequency pattern of changing direction.
\/\ as change of direction as frequency, within a single vector defined by 3 parts
/\/ a 2nd vector composed of three parts as frequency.
So here we now have a new kind of tow involving the actual line/vector of relationship, instead of the previous scenario using generlisd/cosmic duality set of two terminal points.
So we take the 2 vectors two a 2nd power and we get a resultant set of 4 triangles integrated as a 3D volumetric tetra{4}hedron.
2^2 = 4 using a differrent initial set yet same end resultant, a tetrahedron, with or without the three right angles, so this method is less specific than the previous set that used XYZ terminal points.
Observed time is at minimum a 2nd powering of 2, either cosmic set of terminal twoness, or vectorial frequency set of twoness.
r6